Помогите срочно: решите неравенство x^2-3x-4 больше 0

[latex](x-4)(x+1)\ \textgreater \ 0[/latex] [latex] \left \{ {{x-4\ \textgreater \ 0} \atop {x+1\ \textgreater \ 0}} \right. \left \{ {{x-4\ \textless \ 0} \atop {x+1\ \textless \ 0}} \right. [/latex] x>4 x>-1 x<4 x<-1 x∈(-∞;-1)∪(4;+∞)

[latex]x^2-3x-4\ \textgreater \ 0 \left \{ {{x-4\ \textgreater \ 0} \atop {x+1\ \textgreater \ 0} \right. \left \{ {{x-4\ \textless \ 0} \atop {x+1\ \textless \ 0}} \right. \left \{ {{x\ \textgreater \ 4} \atop {x\ \textgreater \ -1}} \right. \left \{ {{x\ \textless \ 4} \atop {x\ \textless \ -1}} \right. [/latex] x∈(4,+∞) x∈(-∞,-1)