Помогите срочно!√(4 + 2 √(3)) - √(4 - 2 √(3))

[latex]\sqrt{4+2\sqrt{3}}=\sqrt{3+2\sqrt{3}+1}=\sqrt{(\sqrt{3})^2+2*\sqrt{3}*1+1^2}=\\\\\sqrt{(\sqrt{3}+1)^2}=|\sqrt{3}+1|=\sqrt{3}+1[/latex] [latex]\sqrt{4-2\sqrt{3}}=\sqrt{3-2\sqrt{3}+1}=\sqrt{(\sqrt{3})^2-2*\sqrt{3}*1+1^2}=\\\\\sqrt{(\sqrt{3}-1)^2}=|\sqrt{3}-1|=|1-\sqrt{3}|=\sqrt{3}-1[/latex] [latex]\sqrt{4+2\sqrt{3}}-\sqrt{4-2\sqrt{3}}=\sqrt{3}+1-(\sqrt{3}-1)=\sqrt{3}+1-\sqrt{3}+1=2[/latex]