Помогите вычеслить.(Хоть частично) Z1+Z2, Z1-Z2, Z1•Z2, Z1÷Z2, -Z1, ÷Z2, если Z1=2+3i, Z1=1-4i

Z₁+Z₂ = (2 + 3i) + (1 - 4i) = 3 - i Z₁-Z₂ = (2 + 3i) - (1 - 4i) = 1 + 7i Z₁·Z₂ = (2 + 3i)(1 - 4i) = 2 - 8i + 3i + 12 = 14 - 5i [latex] \frac{Z_1}{Z_2}= \frac{2+3i}{1-4i} =\frac{(2+3i)(1+4i)}{1+4^2}=\frac{2+8i+3i-12}{17}=\frac{-10+11i}{17}=\frac{-10}{17}+\frac{11}{17}i \\ \\ \frac{-Z_1}{Z_2}= -\frac{Z_1}{Z_2}= \frac{10}{17}-\frac{11}{17}i[/latex]