ПОМОГИТЕ,ПОЖАЛУЙСТА УПРОСТИТЬ! (егэ профиль)

[latex]b^{0.5}=\sqrt{b}[/latex] ------------- 1) [latex]\frac{2+2b^{0.5}}{b^{1.5}-b^{0.5}}=[/latex] [latex]\frac{2*1+2*b^{0.5}}{b^{0.5}*b^1-1*b^{0.5}}=[/latex] [latex]\frac{2(1+b^{0.5})}{b^{0.5}*(b^{0.5*2}-1^2)}=[/latex] [latex]\frac{2(1+b^{0.5})}{b^{0.5}*(b^{0.5}-1)(b^{0.5}+1)}[/latex] [latex]=\frac{2}{b^{0.5}(b^{0.5}-1)}=\frac{2}{\sqrt{b}(\sqrt{b}-1)}[/latex] 2) [latex]\frac{b^{-0.5}}{\sqrt{b}-1}:\frac{\sqrt{b}}{b-2\sqrt{b}+1}=[/latex] [latex]\frac{1}{\sqrt{b}(\sqrt{b}-1)}*\frac{(\sqrt{b}-1)^2}{\sqrt{b}}[/latex] [latex]=\frac{\sqrt{b}-1}{b}[/latex] 3) [latex]\frac{2}{\sqrt{b}(\sqrt{b}-1)}+\frac{\sqrt{b}-1}{b}=[/latex] [latex]\frac{2\sqrt{b}+(\sqrt{b}-1)^2}{b(\sqrt{b}-1)}=[/latex] [latex]\frac{2\sqrt{b}+b-2\sqrt{b}+1}{b(\sqrt{b}-1)}=[/latex] [latex]\frac{b+1}{b(\sqrt{b}-1)}[/latex] 4) [latex]\frac{b+1}{b\sqrt{b}-1}*(\sqrt{b}-1)=\frac{b+1}{b}[/latex]