Помогите,умоляю! 6 sin^2x+sinx cos x- cos^2x=0

6sin^2x+sinxcosx-cos^2=0  | : cos^2x не равен 0 6tg^2x+tgx-1=0 tgx=t 6t^2+t-1=0 D=1^2-4*6*(-1)=1+24=25 t1;2=[latex] \frac{-1+- \sqrt{25} }{6*2} [/latex] t1=[latex] \frac{-1+5}{12} = \frac{4}{12} = \frac{1}{3} [/latex] t2=[latex] \frac{-1-5}{12} = -\frac{6}{12} =- \frac{1}{2} [/latex] tgx=[latex] \frac{1}{3} [/latex]             tgx=[latex] -\frac{1}{2} [/latex]            x=arctg([latex] \frac{1}{3} [/latex])+[latex] \pi n[/latex] , n ∈ Z x=-arctg([latex] \frac{1}{2} [/latex])+[latex] \pi n[/latex] , n ∈ Z