Пожалуйста!!!!!!!ПОМОГИТЕ!!!!!!!!!!!!! Решите неравенства

[latex]1)\; \; (\frac{3}{4})^{x^2} \geq (\frac{4}{3})^{2x-3}\\\\(\frac{3}{4})^{x^2} \geq (\frac{3}{4})^{3-2x}\; \; \; \to \; \; \; x^2 \leq 3-2x\\\\x^2+2x-3 \leq 0\; ,\; \; \; x_1=-3,\; \; x_2=1\\\\(x+3)(x-1) \leq 0\\\\+++[-3]---[1]+++\\\\x\in [\, -3,1\, ][/latex] [latex]2)\; \; 9^{t}+5\cdot 3^{2t}\ \textgreater \ 4^{t}+3\cdot 2^{2t}\\\\9=3^2\; ,\; 4=2^2\\\\3^{2t}+5\cdot 3^{2t}\ \textgreater \ 2^{2t}+3\cdot 2^{2t}\\\\6\cdot 3^{2t}\ \textgreater \ 4\cdot 2^{2t}\, |:2^{2t}\ \textgreater \ 0\\\\6\cdot \frac{3^{2t}}{2^{2t}}\ \textgreater \ 4\, |:6\ \textgreater \ 0\\\\(\frac{3}{2})^{2t}\ \textgreater \ \frac{4}{6}\; \; \; \; (\; \frac{4}{6}=\frac{2}{3}\; )\\\\(\frac{3}{2})^{2t}> (\frac{3}{2})^{-1}\\\\2t> -1\\\\t> -\frac{1}{2}\\\\t\in (-\frac{1}{2},+\infty )[/latex]