Прошу помогите пожалуйста, очень нужно!) 1)Sin5x = -sinx 2)Sinx/2*sinx=0

1)Sin5x = -sinx Sin5x + sinx = 0 2*[sin(5x + x)/2]*[cos(5x - x)/2] = 0 [sin(6x)/2]*[cos(4x)/2] = 0 [sin(3x)]*[cos(2x)] = 0 a)   sin3x = 0 3x = πn, n∈Z x1 = πn/3, n∈Z b)  cos2x = 0 2x = π/2 + πk, k∈Z x2 = π/4 + πk/2, k∈Z 2) sin(x/2)*sinx = 0 a)  sin(x/2) = 0 x/2 = πk, k∈Z x1 = 2πk, k∈Z b)  sinx = 0 x2 = πn, n∈ Z