Пж помогите #40(3)срочно!!!!!

[latex] \frac{83^2-17^2}{81^2-15^2} = \frac{(83-17)(83+17)}{(81-15)(81+15)} = \frac{66*100}{66*96} = \frac{6600}{6336} = \frac{25}{24} =1 \frac{1}{24} [/latex]