Решение неравенств,log

ОДЗ:2х+7>0 2х> -7 Х> -3,5 log1/2 (2x+7)^1/3 <= - log1/2 1/2 log1/2 (2x+7)^1/3 <=log1/2(1/2)^-1 (2x+7)^1/3 <= 2 2x+7<=8 2x <= 1 X<=1/2 /////////////////////// -----(-3,5)--------(1/2)----- \\\\\\\\\\\\\\\\\\\\\\ Ответ: (-3,5 ; 1/2] ОДЗ Х>0 lg9^1/2-lgx>lg3 lg 3/x>lg3 3/Х>3 3х<3 Х<1 Х€(0;1)