Решить неравенство! Cрочно! [latex]( \sqrt[3]{3} ) ^{x+6} \ \textgreater \ \frac{1}{9} [/latex]

[latex]\displaystyle (\sqrt[3]{3})^{x+6}\ \textgreater \ \frac{1}{9} [/latex] [latex]\displaystyle 3^{1/3*(x+6)}\ \textgreater \ 3^{-2}[/latex] [latex]\displaystyle \frac{1}{3}x+2\ \textgreater \ -2 [/latex] [latex]\displaystyle \frac{1}{3}x\ \textgreater \ -4 [/latex] [latex]\displaystyle x\ \textgreater \ -12[/latex]