Решить неравенство [latex] \sqrt{1-4x} \geq 2x+1[/latex] пожлуйста быстреееее((((

[latex] \sqrt{1-4x} \geq 2x+1, \\ \left [ {{ \left \{ {{2x+1\ \textless \ 0,} \atop {1-4x \geq 0,}} \right. } \atop { \left \{ {{2x+1 \geq 0,} \atop {1-4x \geq (2x+1)^2}} \right. }} \right. \left [ {{ \left \{ {{2x\ \textless \ -1,} \atop {-4x \geq -1,}} \right. } \atop { \left \{ {{2x \geq -1,} \atop {1-4x \geq 4x^2+4x+1,}} \right. }} \right. \left [ {{ \left \{ {{x\ \textless \ -0,5,} \atop {x \leq 0,25,}} \right. } \atop { \left \{ {{x \geq -0,5,} \atop {4x^2+8x \leq 0,}} \right. }} \right. \left [ {{ x<-0,5, } \atop { \left \{ {{x \geq -0,5,} \atop {x(x+2) \leq 0,}} \right. }} \right. \left [ {{ x<-0,5, } \atop { \left \{ {{x \geq -0,5,} \atop {-2 \leq x \leq 0,}} \right. }} \right. [/latex] [latex] \left [ {{ x\ \textless \ -0,5, } \atop { -0,5 \leq x \leq 0, }} \right. \\ x \leq 0, \\ x\in(-\infty;0].[/latex]