Решить систему уравнений 2х-у=1 и 5х+у=25

y=2x-1 5x+(2x-1)=25 5x+2x-1=25 7x=26 x=26/7 x=

[latex] \left \{ {{2x-y=1} \atop {5x+y=25}} \right. ; \left \{ {{y=2x-1} \atop {y=25-5x}} \right. \\ [/latex] 2х - 1 = 25 - 5х 2х + 5х = 25 + 1 7х = 26 х = 26 : 7 [latex]x=3 \frac{5}{7} [/latex] [latex]y=2*3 \frac{5}{7} -1[/latex] [latex]y=6 \frac{3}{7} [/latex] Ответ:  [latex]x=3 \frac{5}{7} [/latex] [latex]y=6 \frac{3}{7} [/latex]