Решить \sqrt{11-4 \sqrt{7} } + \sqrt{16- 6\sqrt{7} }

[latex] \sqrt{11-4 \sqrt{7}}+ \sqrt{16-6 \sqrt{7}}= \sqrt{7-2*2 \sqrt{7}+4}+\sqrt{9-2*3*\sqrt{7}+7}= \\ =\sqrt{(\sqrt{7})^2-2*2 \sqrt{7}+2^2}+\sqrt{3^2-2*3*\sqrt{7}+(\sqrt{7})^2}= \\ =\sqrt{(\sqrt{7}-2)^2}+\sqrt{(3- \sqrt{7})^2}=|\sqrt{7}-2|+|3- \sqrt{7}|= \\ =\sqrt{7}-2+3- \sqrt{7}=1[/latex]