Решить тригонометрическое уравнение cos6x- корень из 3 sin 6x=-1

cos(6x) = cos^2(3x) - sin^2(3x) sin(6x) = 2sin(3x)*cos(3x) cos^2(3x) - sin^2(3x) - 2√3*sin(3x)*cos(3x) = -cos^2(3x) - sin^2(3x) 2cos^2(3x) - 2√3*sin(3x)*cos(3x) = 0 2cos(3x)*(cos(3x) - √3*sin(3x)) = 0 1) cos(3x) = 0, 3x = π/2 + πk, x = π/6 + πk/3 2) √3*sin(3x) = cos(3x), tg(3x) = 1/√3, 3x = π/6 + πk, x = π/18 + πk/3