Решить уравнениеа) tgx=-√3 б) 2sin²x+sinx-1

x=arctg a+πn x=arctg√3+πn x=π/3+πn 2 sin2x – sinx = 0 sinx (2 sinx – 1) = 0 sinx = 0                                  2sinx – 1 = 0 x 1 = π/2 + πk, k Є R                sinx = ½                                                 x 2 = π/6 + 2 πk,  k Є R                                                 x 3 = 5π/6 + 2 πk,  k Є R