Решите!!! 13sin^2(x)+84sin2x-13cos^2(x)+1=2sin18*cos18/cos54

[latex]\displaystyle 13sin^2x+84sin(2x)-13cos^2x+1= \frac{2sin18*cos18}{cos54} [/latex] [latex]\displaystyle 13sin^2x+168sinx*cosx-13cos^2x+1= \frac{sin 36}{cos54} [/latex] [latex]\displaystyle 13sin^2x+168sinx*cosx-13cos^2x= \frac{cos(90-36)}{cos54}-1 [/latex] [latex]\displaystyle 13sin^2x+168sinx*cosx-13cos^2x=0[/latex] разделим на cos²x≠0 [latex]\displaystyle 13tg^2x+168tgx-13=0 D=28224+676=28900=170^2[/latex] [latex]\displaystyle tg x=(-168+170)/26=1/13[/latex] [latex]\displaystyle tg x=(-168-170)/26=-13[/latex] [latex]\displaystyle x=arctg (-13)+ \pi n, n\in Z[/latex] [latex]\displaystyle x=arctg(1/13)+ \pi n, n\in Z[/latex]