Решите на множестве R систему неравенства:(9x+9)(x-4) больше 9x²+x+5=2x-3-(x-3)≤5=

[latex] \left \{ {{(9x+9)(x-4) > 9x^2+x+5} \atop {2x-3-(x-3)\leq5}} \right.\\ \left \{ {{9x^2-27x-36 > 9x^2+x+5} \atop {2x-3-x+3\leq5}} \right.\\ \left \{ {{9x^2-27x-36-9x^2-x-5>0} \atop {x\leq5}} \right.\\ \left \{ {{-28x-41>0} \atop {x\leq5}} \right.\\ \left \{ {{-28x>41} \atop {x\leq5}} \right.\\ \left \{ {{x<-\frac{41}{28}} \atop {x\leq5}} \right.\\ x<-\frac{41}{28} [/latex]