Решите неравенство!! 1) 3x-4(2x-8) меньше -3 2) 6x-3(4x+1) больше 6

[latex]3x-8x+32\ \textless \ -3\\\\ -5x\ \textless \ -3-32 \\ \\ -5x\ \textless \ -35 \\ \\ x \ \textgreater \ 7 \\ \\ \\ 6x-12x-3\ \textgreater \ 6 \\ \\ -6x\ \textgreater \ 6+3 \\ \\ -6x\ \textgreater \ 9 \\ \\ x\ \textless \ -\frac{3}{2}[/latex]

1) 3x-4(2x-8) < -3 3x-8x+32<-3 -5x<-35 x>7 x∈(7;∞) 2) 6x-3(4x+1) > 6 6x-12x-3>6 -6x>9 x<-1,5 x∈(-∞;-1,5)