Решите неравенство: [latex]( \frac{1}{5})^{3x-7}\ \textgreater \ 0,04 [/latex]

(1/5)³ˣ⁻⁷>(1/5)² 3x-7<2 3x<9 x<3,  (-∞;3)

[latex] (\frac{1}{5} )^{3x-7}\ \textgreater \ 0,04\\\\(5^{-1})^{3x-7}\ \textgreater \ 5^{-2}\; \; \; (0,04=\frac{4}{100}=\frac{1}{25}=\frac{1}{5^2}=5^{-2})\\\\-3x+7>-2\\\\3x< 9\\\\x<3\\\\x\in (-\infty ;\; 3)[/latex]