Решите неравенство √x²−8x+6+√4x−x²−3 меньше x−1

[latex] \sqrt{2} -8+6+2-2-3\ \textless \ -1; \sqrt{2} -5\ \textless \ -1; [/latex] т.к. [latex] \sqrt{1}\ \textless \ \sqrt{2}\ \textless \ \sqrt{4}, 1\ \textless \ \sqrt{2}\ \textless \ 2, [/latex] то неравенство верное