Решите первый номер пожалуйста

sin(360+60)+cos(360-60)-tg(180+30)=sin60+cos60-tg30= =√3/2+1/2-√3/3 sin(2π-π/4)-cos(2π-π/3)=-sinπ/4-cosπ/3=√2/2-1/2

[latex]sin420+cos300-tg210=\\\\=sin(360+60)+cos(360-60)-tg(180+30)=\\\\=sin60+cos60+tg30=\frac{\sqrt3}{2}+\frac{1}{2}+\frac{\sqrt3}{3}= \frac{3\sqrt3+3+2\sqrt3}{6} =\frac{5\sqrt3+3}{6}\\\\2)\quad sin\frac{7}{4}\pi -cos\frac{5}{3}\pi =sin(2\pi -\frac{\pi}{4})-cos(2\pi -\frac{\pi}{3})=\\\\=-sin\frac{\pi}{4}-cos\frac{\pi}{3}= -\frac{\sqrt2}{2}-\frac{1}{2}=-\frac{\sqrt2+1}{2} [/latex]