Решите плиз.Упростить 1)а² -b² -c²+2bc ----------------- b²-c²-a²-2ac 2) b4(степень)+4 -------------------- b²-2b+2

1) [latex] \frac{a^2-b^2-c^2+2bc}{b^2-c^2-a^2-2ac} = \frac{a^2-(b-c)^2}{b^2-(c+a)^2}= \frac{(a-b+c)(a+b-c)}{(b-c-a)(b+c+a)}= \frac{-(b-a-c)(a+b-c)}{(b-a-c)(a+b+c)}=- \frac{a+b-c}{a+b+c} [/latex] 2) [latex] \frac{b^4+4}{b^2-2b+2}= \frac{b^4-2b^3+2b^2+2b^3-4b^2+4b+2b^2-4b+4}{b^2-2b+2}= [/latex] [latex]= \frac{(b^2-2b+2)(b^2+2b+2)}{b^2-2b+2} =b^2+2b+2[/latex]