Решите пожалуйста 1,4 и если можно 6 пример Свойства логарифмов.Спасибо

[latex]\displaystyle 10^{1+lg19}*log_37*Log_{49}9=10^1*10^{Lg19}* \frac{1}{Log_73}* \frac{1}{2}Log_73^2= [/latex] [latex]\displaystyle 10*19* \frac{2}{2}* \frac{Log_73}{Log_73}=190 [/latex] **************** [latex]\displaystyle 10^{lg80-1}-4Log_{25} \sqrt{5^3}- \frac{1}{2}Log_5(1- \sqrt{2})^2-Log_5(1+ \sqrt{2})= [/latex] [latex]\displaystyle= \frac{80}{10}- \frac{4}{2}Log_55^{3/2}-Log_5|1- \sqrt{2}|-Log_5(1+ \sqrt{2})= [/latex] [latex]\displaystyle= 8-3-(Log_5( \sqrt{2}-1)+Log_5(1+ \sqrt{2}))=8-3-(Log_5(2-1))= [/latex] [latex]\displaystyle= 8-3-0=5[/latex] ******************* [latex]\displaystyle = (3^{3*1/3}*2^{3*2/3}*2^{5*2/5}*3^{4*3/4})^{1/4}+Log_22^{3/2}+[/latex] [latex]\displaystyle+ 2^{ \frac{Log_25}{Log_23}}-5^{Log_32}=[/latex] [latex]\displaystyle = (3^4*2^4)^{1/4}+3/2+5^{ \frac{1}{Log_23}}-5^{ \frac{1}{Log_23} }=[/latex] [latex]\displaystyle = 3*2+3/2+0=7.5[/latex]