Решите пожалуйста 3 задание 1 варианта много баллов дам)

z1=1-i |z1|=√(1+1)=√2 argz1=arctg(-1)=-π/4 z1^100=(√2)^100*(cos(-π/4*100)+isin(-π/4*100))=2^50*(cos(-25π)+isin(-25π))= =2^50*(cos(-π)+Isin(-π))=-2^50 z2=√3+i |z2|=√(3+1)=2 argz2=arctg√3=π/3 z2^50=2^50*(cos(π/3*50)+isin(π/3*50)=2^50*(cos(8π+2π/3)+isin(8π+π/3))= =2^50*(cosπ/3+isinπ/3)=2^50*(1/2+i*√3/2)=2^50*(1+i√3)/2 z=z1/z2=-2√50:2^49*(1+i√3)=2/(1+i√3)=2(1-i√3)/(1-i√3)(1+i√3)= =2(1-i√3)/(1+3)=(1-i√3)/2=1/2-i*√3/2