Решите пожалуйста |√8-3|= ? √(√17-4)^2

[latex]|\sqrt{8}-3|=-(\sqrt{8}-3)=3-\sqrt{8};\\\sqrt{(\sqrt{17}-4)^2}=|\sqrt{17}-4|=\sqrt{17}-4[/latex]

[latex]1)\quad |\sqrt8-3|=-(\sqrt8-3)=3-\sqrt8\; ,\\\\\; tak\; kak\; \; \sqrt8\ \textless \ \sqrt9\; ,\; \; \sqrt8\ \textless \ 3\; \; \Rightarrow \; \; \sqrt8-3\ \textless \ 0\\\\2)\quad \sqrt{(\sqrt{17}-4)^2}=|\sqrt{17}-4|=\sqrt{17}-4\; ,\\\\tak\; kak\; \; \sqrt{17}\ \textgreater \ \sqrt{16}\; ,\; \; \sqrt{17}\ \textgreater \ 4\; \; \Rightarrow \; \; \sqrt{17}-4\ \textgreater \ 0\\\\\\P.S.\quad \sqrt{a^2}=|a|= \left \{ {{a\; ,\; esli\; a \geq 0} \atop {-a\; ,\; esli\; a\ \textless \ 0}} \right. [/latex]