Решите пожалуйсто 1 врянт

1. а) (3+а)(2а+1)=6а+3+2а^2+а=2а^2+ +7а+3 б) (5а+а^2)(3–2а)=15а–10а^2+3а^2– –2а^3=15а–7а^2–2а^3 в) (3–х)(2–4х)=6–12х–2х+4х^2=4х^2 –14х+6 г) (–х–3)(2х–4)=–2х^2+4х–6х+12= =12–2х^2–2х 2. а) 8–(2+а)(3а+4)=8–6а–8–3а^2–4а=–3а^2–10а б) 2а^3+(а+а^2)(5–2а)=2а^3+5а–2а^2+5а^2–2а^3=5а+3а^2 в) (1–х)(2+2х)+(2–х)(1–2х)=2+2х–2х– –2х^2+2–4х–х+2х^2=4–5х г) (х–2)(х–5)–(х–3)(х–4)=х^2–5х–2х+ +10–х^2+4х+3х–12=-2 3. а) 3х(х–2) б) (х–3)(х–8) 4. а) 3(х–4)+х^2–4х=3(х–4)+х(х–4)= =(х–4)(3+х) б) 2х–8–х(х–4)=2(х–4)–х(х–4)=(х–4)(2–х) в) х^3+5х^2–2х–10=х^2(х+5)–2(х+5) = (х+5)(х^2–2) г) х^3–6х^2–2х+12=х^2(х–6)–2(х–6) = (х–6)(х^2–2)