Решите пожл 4 номер очень срочно

[latex]y=2sinx+3\\\\y'=2cosx=0\; \; \to \; \; x=\frac{\pi}{2}+\pi n= \left \{ {{\frac{\pi}{2}+2\pi n\; n\in Z} \atop {-\frac{\pi}{2}+2\pi k,\; k\in Z}} \right. \\\\+++(-\frac{3\pi}{2})---(-\frac{\pi}{2})+++(\frac{\pi}{2})---(\frac{3\pi}{2})+++\\\\x_{max}=\frac{\pi}{2}+2\pi n,\; n\in Z\\\\x_{min}=-\frac{\pi}{2}+2\pi k, \; k\in Z}\\\\y_{max}=y(\frac{\pi}{2}+2\pi n)=2sin(\frac{\pi}{2}+2\pi n)+3=2\cdot 1+3=5\\\\y_{min}=y(-\frac{\pi}{2}+2\pi k)=2sin(-\frac{\pi}{2}+2\pi k)+3=2\cdot (-1)+3=1[/latex]