Решите пжлст! log3(x)*log2(x)=4log3(2) И вот это log5(x)*log3(x)=9log5(3)

1) Используем равенство log2(x) = log3(x)/log3(2): log3(x) * log3(x)/log3(2) = 4log3(2) (log3(x))^2 = (2log3(2))^2 (log3(x))^2 = (log3(4))^2 log3(x) = log3(4) или log3(x) = -log3(4) x = 4 или x = 1/4 2) log5(x) = log3(x)/log3(5) = log3(x) * log5(3) log3(x) * log3(x) * log5(3) = 9log5(3) (log3(x))^2 = 9 log3(x) = 3 или log3(x) = -3 x = 3^3 или x = 3^(-3) x = 27 или x = 1/27