Решите систему 3х-у=1 ху=10

[latex] \left \{ {{3x-y=1}\atop {x= \frac{10}{y} }} \right. \\ \\ 3* \frac{10}{y} -y=1 \\ \\ \frac{10- y^{2} }{y} = \frac{1}{3} \\ \\ 30-3 y^{2} =y \\ \\ 3 y^{2} +y-30=0 \\ \\ D=1+360=361 \\ \\ y1= \frac{-1-19}{6} = -\frac{10}{3} \\ \\ y2= \frac{18}{6} =3[/latex]