Решите систему неравенств[latex] \left \{ {{5 x+13 \leq 0} \atop {x+5 \geq 1}} \right. [/latex]

[latex] \left \{ {{5x+13 \leq 0} \atop {x+5 \geq 1}} \right. \\ \left \{ {{5x \leq -13} \atop {x \geq 1-5}} \right. \\ \left \{ {{x \geq - \frac{13}{5} } \atop {x \geq -4}} \right. \\ \left \{ {{x \geq - 2.6} \atop {x \geq -4}} \right. [/latex] Ответ: x∈[2.6; знак бесконечности)