Решите систему уравнений {х+2у=5, х/4+(у+6)/3=3

[latex] \left \{ {{x+2y = 5} \atop { \frac{x}{4} + \frac{y+6}{3} = 3 }} \right. [/latex] [latex]\left \{ {{x = 5 - 2y} \atop {3x+ 4y+24 = 36 }} \right.[/latex] [latex]\left \{ {{x = 5 - 2y} \atop {3(5-2y)+ 4y+24 = 36 }} \right.[/latex] [latex]\left \{ {{x = 5 - 2y} \atop {15-2y+24 = 36 }} \right.[/latex] [latex]\left \{ {{x = 5 - 2y} \atop {y = 1,5 }} \right.[/latex] x = 5 - 2 * 1,5 = 2.