Решите уравнение 1) 5^x-1+5^x+1=130 2) 7*3^2x-6*3^x-1=0

[latex]5^{x-1}+5^{x+1}=130 \\ \\ \frac{1}{5} \cdot 5^x+5\cdot5^x=130 \\ \\ 5^x+25\cdot5^x=130\cdot5 \\ \\ 26\cdot5^x=130\cdot5 \\ \\ 5^x=5^2 \\ \\ x=2[/latex] [latex]7\cdot3^{2x}-6\cdot3^x-1=0 \\ \\ 3^{x}=t(t>0) \\ \\ 7t^2-6t-1=0 \\ \\ D=b^2-4ac=64 \\ \\ t_1=- \frac{1}{7} ;\,\,\,\,\,\,\,\,\,\,\,\,t_2=1 \\ \\ 3^x=1[/latex] [latex]x=0[/latex]