Решите уравнение 13x^2-2/3=(3-4x)^2-1/3(3x-2)(3x+2)

[latex]13 x^{2} - \frac{2}{3}=(3-4x)^{2}- \frac{1}{3}(3x-2)(3x+2) [/latex] [latex]\frac{39 x^{2} -2}{3}= \frac{9-24x+16 x^{2} -9 x^{2} +4}{3} [/latex] [latex]\frac{39 x^{2} -2}{3}-\frac{12-24x+7x^{2}}{3}=0 [/latex] [latex]\frac{39 x^{2} -2-12+24x-7x^{2}}{3}=0 [/latex] [latex]39 x^{2} -2-12+24x-7x^{2}=0 [/latex] 32x² -14+24x=0 [ 16x² -7+12x=0  D=144-4*(-7)*14