Решите уравнение 3/х-8+8/х-3=2

[latex] \frac{3}{x-8} + \frac{8}{x-3} =2 \\ \\ \frac{3(x-3)+8(x-8)}{(x-8)(x-3)} =2 \\ \\ \frac{11x-73}{x^2-11x+24} =2 \\ \\ 11x-73=2(x^2-11x+24) \\ 11x-73=2x^2-22x+48 \\ 2x^2-33x+121=0 \\ D=(-33)^2-4*2*121=1089-968=121 \\ \\ x_1= \frac{33+11}{2*2} = \frac{44}{4} =11 \\ \\ x_2= \frac{33-11}{2*2} = \frac{22}{4} = \frac{11}{2} =5,5[/latex]