Решите уравнение 9^(х)+2*3^(х+1)-7=0

9 ^ x + 2 * 3 ^ (x + 1) -7 = 0 3 ^ 2x + 2 * 3 ^ ( x + 1 ) - 7 = 0 3 ^ x = a ; a > 0 a + 6a - 7 = 0 D = 36 + 28 = 64; √ D = 8 a1 = ( - 6 + 8 ) : 2 = 1 a2 = ( - 6 - 8 ) : 2 = - 7 ( < 0 ) 3 ^ x = 1 3 ^ x = 3 ^ 0 x = 0