Решите уравнение: х^2-4/х+2=0 , 4-5у/у+5-1+5у/5-у=7/у^2-25

1) (x² -4)/(x+2) =0 (x-2)(x+2)/(x+2) =0 x-2 =0 x =2 2) (4-5y)/(y+5) -(1+5y)/(5-y)=7/(y-5)(y+5) ((4-5y)(5-y) -(1+5y)(y+5)) /(y+5)(5-y) =7/(y-5)(y+5) (20-29y+5y² -(5+5y²+26y)) / -(y+5)(y-5) = 7/(y -5)(y+5) (20-29y+5y²-5-5y²-26y) / -(y-5)(y+5) =7/(y-5)(y+5) -(15-55y)/(y-5)(y+5) = 7/(y -5)(y+5) (-15+55y -7) /(y-5)(y+5) =0 55y -22 =0 55y =22 y =22/55 y =2/5 y =0.4