Решите уравнение х/2х-3=4/х

[latex] \frac{x}{2x-3} = \frac{4}{x} [/latex] 8x-12=[latex] x^{2} [/latex] [latex] x^{2} [/latex]-8x+12=0 D=64-4*1*12 D=64-48=16=[latex] 4^{2} [/latex] x1=(8+4)/16=12/16=3/4=0.75 x2=(8-4)/16=4/16=1/4=0.25