Решите уравнение (x^2-5x)+5-x=0

[latex]( x^{2} -5x) + 5-x=0[/latex] [latex] x^{2} - 6x+5=0[/latex] [latex]D=b^{2} - 4ac= (-6)^{2} -4*1*5=36-20=16[/latex] [latex] \sqrt{D} = \sqrt{16} =4[/latex] [latex] x_{1} = \frac{6+4}{2} = \frac{10}{2} =5[/latex] [latex] x_{2} = \frac{6-4}{2} = \frac{2}{2} =1[/latex] Ответ:5;1