РЕШИТЕ УРАВНЕНИЕ:1)log3x+log9x+log27x=одиннадцать двенадцатых

[latex]log_{3}x +[/latex] [latex]log_{9}x +[/latex] [latex]log_{27}x = \frac{11}{12}[/latex] [latex]log_{3}x +[/latex] [latex]log_{ 3^{2}}x +[/latex] [latex]log_{3^{3}}x = \frac{11}{12}[/latex] [latex]log_{3}x +[/latex] [latex]\frac{1}{2}log_{3}x +[/latex] [latex]\frac{1}{3}log_{3}x = \frac{11}{12}[/latex] [latex]\frac{1}{12}log_{3}x + [/latex][latex]\frac{6}{12}[/latex][latex]log_{3}x + \frac{4}{12}log_{3}x =[/latex] [latex]\frac{11}{12}[/latex] [latex]\frac{11}{12}log_{3}x =[/latex] [latex]\frac{11}{12}[/latex] [latex]log_{3}x = 1[/latex] [latex]x = 3[/latex]