Решите уравнение(х +1)^2=0(х-2)^2=64

(x  + 1)^2 = 0 x + 1 = 0  x = -  1 ============================================== (x - 2)^2 - 64 =  0 (x -  2)^2 - 8^2 = 0  (x - 2  - 8)(x - 2 + 8) = 0 (x - 10)( x + 6) = 0 x - 10 = 0 x  = 10; x + 6 = 0 x = - 6 

(х+1)²=0 х²+2х+1=0 D=4-4=0 x=-2/2=-1 (x-2)²=64 x²-4x+4-64=0 x²-4x-60=0 D=16+240=256       √D=16 x₁=(4+16)/2=10 x₂=(4-16)/2=-6