Решите уравнение:x-[latex] \sqrt{x} [/latex]-12=0

х√х = 12 (x√x)[latex] ^{2} [/latex] = [latex](12) ^{2} [/latex] (x)^2(x) = (12)^2 (x)^2(x) = 144 x^2(x) = 144 x^3 = 144 x = [latex] \sqrt[3]{144} [/latex] x = 2*[latex] \sqrt[3]{18} [/latex] - Потому что х = [latex] \sqrt[3]{2*2*2*18} [/latex] => x = 2[latex] 2\sqrt[3]{18} [/latex] x ≈ 5.24