Решите уравнения [latex]sin(2x+ \frac{PI}{3} )=- \frac{1}{2} [/latex]

[latex]\displaystyle sin(2x+ \pi /3)=- \frac{1}{2} [/latex] [latex]\displaystyle \left \{ {{2x+ \pi /3=5 \pi /4+2 \pi N} \atop {2x+ \pi /3=11 \pi /4+2 \pi N}} \right. [/latex] [latex]\displaystyle \left \{ {{2x= \pi /12+2 \pi N} \atop {2x=7 \pi /12+2 \pi N}} \right. [/latex] [latex]\displaystyle \left \{ {{x= \pi /24+ \pi N} \atop {x=7 \pi /24+ \pi N}} \right. [/latex]