Решите уравнения log2 (8+7x)= log2 (8+3x)+1

log₂(8+7x)=log₂(8+3x)+1 ОДЗ:   [latex] \left \{ {{8+7x\ \textgreater \ 0} \atop {8+3x\ \textgreater \ 0}} \right. , \left \{ {{x\ \textgreater \ - \frac{8}{7} } \atop {x\ \textgreater \ - \frac{8}{3} }} \right. =\ \textgreater \ x\ \textgreater \ - \frac{8}{7} [/latex] 1=log₂2¹=log₂2 log₂(8+7x)=log₂(8+3x)+log₂2 log₂(8+7x)=log₂((8+3x)*2) 8+7x=16+6x x=6