Решите уравнения по алгебре

[latex]1) x^{4} -25 x^{2} =0 \\ x^{2} ( x^{2} -25)=0 \\ x^{2} =0\to x=0 \\ x^{2} -25=0 \\ x^{2} =25 \\ x=+-5[/latex] [latex]2)\frac{ x^{2} +5x-6}{x+1} =0 \\ x^{2} +5x-6=0 \\ D=25+24=49 \ \ \sqrt{D} =7 \\ x_{1} = \frac{-5+7}{2} = \frac{2}{2} =1 \\ x_{2} = \frac{-5-7}{2} =- \frac{12}{2} =-6 \\ x+1 \neq 0 \\ x \neq -1 \\[/latex]