Решите1+3sin^2x=4sinxcosx

1+3sin^2x=4sinxcosx sin^2x+cos^2x+3sin^2x-4sinxcosx=0 4sin^2x-4sinxcosx+cos^2x=0  |: cos^2x 4tg^2x-4tgx+1=0 tgx=a 4a^2-4a+1=0 a=1/2 tgx=1/2 x=arctg1/2+pi*n, n∈Z