Решитеееее плиз  [latex] \frac{4- \sqrt{2} }{4+ \sqrt{2} } - \frac{4+ \sqrt{2} }{4- \sqrt{2} } [/latex]

[latex] \frac{4- \sqrt{2} }{4+ \sqrt{2} } - \frac{4+ \sqrt{2} }{4- \sqrt{2} } = \frac{(4- \sqrt{2} )^2-(4+ \sqrt{2} )^2}{(4+ \sqrt{2} )(4- \sqrt{2} )} = \frac{(4- \sqrt{2} -4- \sqrt{2} )(4- \sqrt{2} + 4+ \sqrt{2} )}{4^2- (\sqrt{2} )^2} = \\ = \frac{-2 \sqrt{2} \cdot8}{16-2} = \frac{-16 \sqrt{2}}{14} = \frac{-8 \sqrt{2}}{7}[/latex]