Снова алгебра, прошу помощи

1 ОДЗ {(1/2-x)(x-4)≥0 {(2x+0,2)/(x+1)>0 x=1/2 x=5            x=-0,1  x=-1                                              /////////////////            -------(-1)-----------(-0,1)------[1/2]---------[4]-------------------- //////////                     \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\  x∈[1/2;4] √(1/2-x)(x-4)≥0⇒log(2)[(2x+0,2)/(x+1)]≤0 (2x+0.2)/(x+1)≤1 (2x+0,2-x-1)/(x+1)≤0 (x-0,8)(x+1)≤0 x=0,8  x=-1 -10⇒x<0,5 U x>3 {log(2)|x-1|>0⇒|x-1|>1⇒x-1<-1 U x-1>1⇒x<0 U x>2 x∈(-∞;0) U (3;∞) 2){(x-1/2)(x-3)<0⇒0,5