Сократить дробь: [latex]\frac{7^{n+1} * 2^{3n-4}}{ 56^{n-1}} [/latex]

[latex] \frac{7^{n+1}*2^{3n-4}}{56^{n-1}}= \frac{7^{n+1}*2^{3n-4}}{(7*2*2*2)^{n-1}}= \frac{7^{n+1}*2^{3n-4}}{(7*2^{3})^{n-1}}= \frac{7^{n+1}*2^{3n-4}}{7^{n-1}*2^{3*(n-1)}}= \\ \\ =\frac{7^{n+1}*2^{3n-4}}{7^{(n-1)}*2^{3n-3}}=7^{n+1-(n-1)}*2^{3n-4-(3n-3)}= \\ \\ =7^{n+1-n+1}*2^{3n-4-3n+3}=7^{2}*2^{-1}= \frac{7^{2}}{2} =49/2=24.5[/latex]