Sqrt(x-5)+sqrt(10-x)=3

[latex] \left \{ {{x \geq 5} \atop {x \leq 10}} \right. [/latex] [latex] x-5 + 2\sqrt{x-5}\sqrt{10-x} + 10 - x = 9[/latex] [latex] 2\sqrt{x-5}\sqrt{10-x} = 4 [/latex] [latex] \sqrt{x-5}\sqrt{10-x} = 2 [/latex] [latex] (x-5)(10-x) = 4 [/latex] [latex] 10x - x^2 - 50 + 5^x = 4 [/latex] [latex] x^2 - 15x + 54 = 0 [/latex] x = 6 или x = 9 это и будет ответом