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[latex]\displaystyle \left \{ {{ (3^{x^2})^y=27^{12}} \atop {2log_2x=Log_2(13-y)}} \right. [/latex] [latex]ODZ: x\ \textgreater \ 0; y\ \textless \ 13[/latex] [latex]\displaystyle \left \{ {{3^{x^2}^y=3^{3*12}} \atop {Log_2x^2=Log_2(13-y)}} \right. [/latex] [latex]\displaystyle \left \{ {{x^2y=36} \atop {x^2=13-y}} \right. [/latex] [latex]\displaystyle (13-y)y=36 13y-y^2=36 y^2-13y+36=0 D=169-144=25=5^2 y_1=9 y_2=4[/latex] [latex]y_1=9 x^2_1=13-9 x^2_1=4 x=+/-2 [/latex] по ODZ x=2 [latex]\displaystyle y_2=4 x^2_2=13-4=9 x_2=+/-3[/latex] по ODZ x=3 Ответ : [2;9] и [3;4]